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4x^2+0.76x-0.9804=0
a = 4; b = 0.76; c = -0.9804;
Δ = b2-4ac
Δ = 0.762-4·4·(-0.9804)
Δ = 16.264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.76)-\sqrt{16.264}}{2*4}=\frac{-0.76-\sqrt{16.264}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.76)+\sqrt{16.264}}{2*4}=\frac{-0.76+\sqrt{16.264}}{8} $
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